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a scientist measures the diameter of two very thin wires to be used in an electrical experiment. the diameter of the first wire is 1.24*10^-3 mm. the diameter of the second wire is 9.1*10^-4 mm. how much wider is the first wire than the second one?

 Feb 11, 2015

Best Answer 

 #1
avatar+101424 
+5

1.24 x 10^-3   =   .00124

And

9.1 x 10^-4  =  .00091

So, we just subtract like we normally would....

   .00124

-  .00091

  ----------

   .00033mm

And that's it !!!

 

 Feb 11, 2015
 #1
avatar+101424 
+5
Best Answer

1.24 x 10^-3   =   .00124

And

9.1 x 10^-4  =  .00091

So, we just subtract like we normally would....

   .00124

-  .00091

  ----------

   .00033mm

And that's it !!!

 

CPhill Feb 11, 2015

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