+0  
 
0
581
1
avatar+136 

a scientist measures the diameter of two very thin wires to be used in an electrical experiment. the diameter of the first wire is 1.24*10^-3 mm. the diameter of the second wire is 9.1*10^-4 mm. how much wider is the first wire than the second one?

 Feb 11, 2015

Best Answer 

 #1
avatar+107156 
+5

1.24 x 10^-3   =   .00124

And

9.1 x 10^-4  =  .00091

So, we just subtract like we normally would....

   .00124

-  .00091

  ----------

   .00033mm

And that's it !!!

 

 Feb 11, 2015
 #1
avatar+107156 
+5
Best Answer

1.24 x 10^-3   =   .00124

And

9.1 x 10^-4  =  .00091

So, we just subtract like we normally would....

   .00124

-  .00091

  ----------

   .00033mm

And that's it !!!

 

CPhill Feb 11, 2015

11 Online Users