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a small rectangular park is being desinged. the perimeter is 340 ft total. the width is 100 ft less than the length. what's the L/W?

Guest Sep 3, 2014

Best Answer 

 #1
avatar+4472 
+10

Let's set up an equation after defining some variables:

 

L = length & W = width

 

W = L - 100 (width is 100 feet less than the length)

 

Perimeter of a rectangle is 2L + 2W...

 

2L + 2(L - 100) = 340.

 

Distribute the 2.

2L + 2L - 200 = 340.

 

Combine like terms and add 200 to both sides.

4L = 540.

 

Solve for L.

L = 540/4 = 135.

 

So, W = L - 100 = 135 - 100 = 35.

 

L = 135 ft.

W = 35 ft.

 

Check: 2L + 2W = 340.

2(135) + 2(35) = 340.

270 + 70 = 340. Yes.

AzizHusain  Sep 3, 2014
 #1
avatar+4472 
+10
Best Answer

Let's set up an equation after defining some variables:

 

L = length & W = width

 

W = L - 100 (width is 100 feet less than the length)

 

Perimeter of a rectangle is 2L + 2W...

 

2L + 2(L - 100) = 340.

 

Distribute the 2.

2L + 2L - 200 = 340.

 

Combine like terms and add 200 to both sides.

4L = 540.

 

Solve for L.

L = 540/4 = 135.

 

So, W = L - 100 = 135 - 100 = 35.

 

L = 135 ft.

W = 35 ft.

 

Check: 2L + 2W = 340.

2(135) + 2(35) = 340.

270 + 70 = 340. Yes.

AzizHusain  Sep 3, 2014

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