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# a small rectangular park is being desinged. the perimeter is 340 ft total. the width is 100 ft less than the length. what's the L/W?

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a small rectangular park is being desinged. the perimeter is 340 ft total. the width is 100 ft less than the length. what's the L/W?

Guest Sep 3, 2014

#1
+4471
+10

Let's set up an equation after defining some variables:

L = length & W = width

W = L - 100 (width is 100 feet less than the length)

Perimeter of a rectangle is 2L + 2W...

2L + 2(L - 100) = 340.

Distribute the 2.

2L + 2L - 200 = 340.

Combine like terms and add 200 to both sides.

4L = 540.

Solve for L.

L = 540/4 = 135.

So, W = L - 100 = 135 - 100 = 35.

L = 135 ft.

W = 35 ft.

Check: 2L + 2W = 340.

2(135) + 2(35) = 340.

270 + 70 = 340. Yes.

AzizHusain  Sep 3, 2014
Sort:

#1
+4471
+10

Let's set up an equation after defining some variables:

L = length & W = width

W = L - 100 (width is 100 feet less than the length)

Perimeter of a rectangle is 2L + 2W...

2L + 2(L - 100) = 340.

Distribute the 2.

2L + 2L - 200 = 340.

Combine like terms and add 200 to both sides.

4L = 540.

Solve for L.

L = 540/4 = 135.

So, W = L - 100 = 135 - 100 = 35.

L = 135 ft.

W = 35 ft.

Check: 2L + 2W = 340.

2(135) + 2(35) = 340.

270 + 70 = 340. Yes.

AzizHusain  Sep 3, 2014

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