A spinner is divided into four equal sections that are numbered 1, 3, 4, and 6. The spinner is spun twice.
How many outcomes have a sum greater than 5 and contain at least one odd number?
Answer choices:
There are 4 * 4 = 16 possible outcomes
1, 3, 4, 6
Let us find the possibilities where the sum is > 5
(1, 6) (6, 1) ( 3, 4) ( 4, 3) (3, 6) (6, 3) ( 4, 6) ( 6, 4) (3, 3) (4, 4) (6, 6)
So the ones that include at least one odd number are
(1,6) (6,1), (3,4) (4,3) (3,6) (6,3) (3,3) = 7