+0  
 
0
538
1
avatar+588 

A spinner is divided into four equal sections that are numbered 1, 3, 4, and 6. The spinner is spun twice.

How many outcomes have a sum greater than 5 and contain at least one odd number?

 

Answer choices:

  • 3
  • 5
  • 7
  • 8
adore.nuk  Feb 3, 2018
 #1
avatar+87691 
+1

There  are 4 * 4  =  16 possible outcomes

 

1, 3, 4, 6

 

Let us find the possibilities where the sum is > 5

 

(1, 6)    (6, 1)  ( 3, 4) ( 4, 3) (3, 6) (6, 3)  ( 4, 6) ( 6, 4) (3, 3) (4, 4) (6, 6)

 

So  the ones that include at least one odd number are

 

(1,6) (6,1), (3,4) (4,3) (3,6) (6,3) (3,3)  =    7

 

 

cool cool cool

CPhill  Feb 4, 2018

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