A sprinkler system on a farm is set to spray water over a distance of 35 meters and to rotate through an angle of 140degrees. find the area

A sprinkler system on a farm is set to spray water over a distance of 35 meters and to rotate through an angle of 140degrees. find the area of the region that can be watered

$$\\ \small{\text{ $A=\pi r^2 $ is the area of the circle. $ A=\pi r^2 *\left( \frac{140\ensurement{^{\circ}}}{360\ensurement{^{\circ}}}\right) $ is the area of the Region can be watered. }} \\ \small{\text{ $ r=35\;m.\quad A=\pi *35^2 *\left( \frac{140\ensurement{^{\circ}}}{360\ensurement{^{\circ}}}\right) = \pi *35^2 *\frac{7}{18} = 1496.62\;m^2$ }}\\ \small{\text{ The area of the Region can be watered is $ \textcolor[rgb]{1,0,0}{1496.62\;m^2 } $ }}$$

A = (1/2)r²Θ  and Θ is in rads, so converting 140° to rads, we have

140° x (pi/180°) = about 2.44 rads....so we have..

A = (1/2)(35m)²(2.44) = 1494.5m²

Thanks and just for laughs.. what does the butcher weigh? meat.