A square with sides of 12 units is inscribed in a circle. What is the value of K if the area of the circle is Kpi square units?

The diagonal of the square, and hence the diameter of the circle, will be \(\sqrt2\times12\)

 

The area of the circle will therefore be:  \(\pi\times(\sqrt2\times12)^2/4\)   

 

Equate this to \(k\times\pi\)   and rearrange to get k