A square with sides of length x, is inside of a circle.
Each vertex of the square is on the circumference of the circle.
The area of the circle is 49cm^2
Work out the value of x and give your answer is 3 significant figures.
What i done:
49/pi = 15.6
sqrt 15.6 = 3.9
3.9*2= 7.8
but my steps so far seems to be wrong please correct and explain to me what i should do
Area of circle is
49 = pi * r^2
49 / pi = r^2 take the square root of both sides
7 / √pi = radius
The diameter is twice this = 14/ √pi = the diagonal of the square
And the diagonal of a square = √2 * side length
So.....we have that
14 / √pi = √2 * side length [divide both sides by √2 ]
14 / √ [ 2 pi ] = side length ≈ 5.585 cm