a squared box of steel has 10 cm each side, we apply 800ºC. If its emisivity is 0.60, which is the total rate of energy emission radiation?

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physics

Guest Jun 7, 2015

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Best Answer

Total energy emission is given by:

$E=A\sigma \epsilon T^4$

where A is area, σ is the Stefan-Boltzmann constant ( ≈ 5.670373×10⁻⁸ W m⁻² K⁻⁴), ε is the emissivity and T is the absolute temperature.

I'll leave you to plug in the numbers.

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Alan Jun 8, 2015

Alan · Answer 1 · 2015-06-08T07:13:02

Total energy emission is given by:

$E=A\sigma \epsilon T^4$

where A is area, σ is the Stefan-Boltzmann constant ( ≈ 5.670373×10⁻⁸ W m⁻² K⁻⁴), ε is the emissivity and T is the absolute temperature.

I'll leave you to plug in the numbers.

.

Guest · Answer 2 · 2015-06-08T11:44:03

Thank you, Alan. Thank you for taking the time to answer. You've helped me a lot.