a squared box of steel has 10 cm each side, we apply 800ºC. If its emisivity is 0.60, which is the total rate of energy emission radiation?
Please detail the answer.
Total energy emission is given by:
E=AσϵT4
where A is area, σ is the Stefan-Boltzmann constant ( ≈ 5.670373×10−8 W m−2 K−4), ε is the emissivity and T is the absolute temperature.
I'll leave you to plug in the numbers.
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Thank you, Alan. Thank you for taking the time to answer. You've helped me a lot.