+13 A student is asked to calculate the Pythagorean Triples for the number 13 using the identity (x^2-y^2)^2 + (2xy)^2 = (x^2 + y^2)^2. The student's steps are shown below
Step 1: 13 = 7^2 - 6^2; therefore, x=7 and y=6
Step 2: (7^2 - 6^2)^2 + (2*7*6)^2 = (7^2+6^2)^2
Step 3: (a-b)^2 + (84)^2 = (49+36)^2
Step 4: (13)^2 + (84)^2 = (c)^2
Step 5: The Pythagorean Triples are 13,84, and 85.
In steps 3 and 4 what are the values of a,b, and c, respectively?
A.) 14,12,84
B.) 49,12,84
C.) 49,36,85
D.) 13,84,85
