a surveyor finds that the angle of elevation to the top of a 1000 ft tower is 67 degrees. How far back would the surveyor have to move so that the angle of elevation to the top of the tower is 55 degrees?
Hey I am doing this problem to and heers my answer,to do this we need to replace the angle of elevation that 67 degrees with 55 degrees.Then we make the equation tan55degrees is equal to 1000/x which is the length from the base of the tower to the surveyor when the angle of elevation is 55 degrees.Then we can multiply both sides by x to get tan55 times x is equal to 1000.Then we divide both sides by tan 55 degrees to get 1000/tan 55 degrees is equal to x.Then we plug that into our calculator to get about 700 ft.Then we compare subtract whatever you get for 67 degrees which would be 425 for me roundede to thenearest foot as 424.47 was the nearest hundred adn 424 to the enarest ones place.so we subtract 424 from 700 ft to get 276.The surveyor would need to move 276 ft back to get an angle of elevation of 55 degrees. JUDGE MY SPELLLING PLEASE LOL also Like this cus I spent so long typing this.
