We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

A triangle has vertices P(−2, 5), Q(−2, −3), and R(4, −3). S is the midpoint of PQ and T is the midpoint of QR. What is the length of ST?

st=5

st=4

st=3 squareroot 2

st= 6 squareroot 2

hayleeirene May 14, 2018

#1**+1 **

Plotting this on a piece of paper, and labeling all the points;

We have S midway of 8, which is 4

We have T midway of 6, which is 3

Thus, we have a right angle triangle, and we use this formula:

a^2+b^2=c^2

Plugging 4 for a, and 3 for b, we have

4^2+3^2=c^2

c^2=25

\(c=\boxed{5}\)

st=5, (a)

.tertre May 14, 2018