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a truck with a 16-inch radius wheels is driven at 77 feet per second. find the measure of the angle through which a point on the outside of the wheel travels each second.

physics
Guest Mar 6, 2015

Best Answer 

 #1
avatar+92624 
+5

a truck with a 16-inch radius wheels is driven at 77 feet per second. find the measure of the angle through which a point on the outside of the wheel travels each second.

 

one revolution = 2pi*r = 32pi     inches

 

77 feet = 77*12 = 924"

 

$$\\\frac{924}{32\pi}\approx 9.19 \;\;rev/sec\\\\\\
\frac{924}{32\pi}\times 2\pi=57.75\;\; radians/sec$$

Melody  Mar 7, 2015
 #1
avatar+92624 
+5
Best Answer

a truck with a 16-inch radius wheels is driven at 77 feet per second. find the measure of the angle through which a point on the outside of the wheel travels each second.

 

one revolution = 2pi*r = 32pi     inches

 

77 feet = 77*12 = 924"

 

$$\\\frac{924}{32\pi}\approx 9.19 \;\;rev/sec\\\\\\
\frac{924}{32\pi}\times 2\pi=57.75\;\; radians/sec$$

Melody  Mar 7, 2015

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