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# aaaaa

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Let $n$ be a positive integer greater than or equal to $3$. Let $a,b$ be integers such that $ab$ is invertible modulo $n$ and $(ab)^{-1}\equiv 2\pmod n$. Given $a+b$ is invertible, what is the remainder when $(a+b)^{-1}(a^{-1}+b^{-1})$ is divided by $n$?

Sep 10, 2020

#1
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The remainder is 2^2 = 4.

Sep 10, 2020
#2
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That is incorrect :(

Guest Sep 10, 2020