ABCD is a rectangle

See CPhill's answer

https://web2.0calc.com/questions/help_7273

The height of this trapezoid is AB and the bases are ZD and WC

We have

120 = (1/2) AB  (ZD + WC)

120 = (1/2) 12 ( ZD + 6)     multiply through by 2

240 = 12 (ZD + 6)      divide both sides by 12

20 =  ZD + 6       subtract 6 from both sides

14 = ZD

Now   angle DBW = angle BDZ

And angle ZQD = angle BQW

And since AZ = WC

Then  ZD = BW

So by AAS....triangle ZQD is congruent to triangle WQZ

And the altitude of trangle DQZ    = altitude of triangle BQW

And since twice these altitudes = AB....then each altitude = 1/2(AB) = 6

So....the area of triangle BQW   =

(1/2) BW * altitude of BQW   = 

(1/2) (14)(6) =

(1/2) (84) =

42 units^2

It is good that you like it Chris, it is your answer.

https://web2.0calc.com/questions/help_7273

JoLink, do not take the credit for other people's answers!

Just say that you have found an answer by CPhill and give the link.

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Linking a question to a good question will give you a good name.

Taking credit for other people's answers is plagiarism. It is immoral and very rude.

Taking credit for other people's work gives you a bad name.