Mathx: Funktion f(x) = Wurzel aus x
[input]diff( sqrt(x), x )[/input]
f'(x) = (1/2)/(sqrt(x)) =1 / ( 2* sqrt(x) )
f'(1)= 1 / ( 2 * sqrt(1) ) = 1 / 2
f(x) = sqrt(x) = x^(1/2)
somit:
f'(x) = (1/2) * x^(1/2 - 1) =
1/2 * x^(-1/2) =
(1/2) / x^(1/2) ) =
(1/2) / sqrt( x ) =
1/(2*sqrt(x))
+3146 
