#1**+5 **

Take both things out of the absolute value bars and solve two equations

2v + 3 = 2v + 6 and -(2v + 3) = 2v + 6

The first equation has no real solutions

For the second, we have

-2v - 3 = 2v + 6 subtract 2v from both sides and add 3 to both sides

-4v = 9 divide both sides by -4

v = -9/4 = -2.25

Here's a graph of the solution using "x" imstead of "v"...... https://www.desmos.com/calculator/zdbtixc1np

CPhill
Sep 15, 2014

#1**+5 **

Best Answer

Take both things out of the absolute value bars and solve two equations

2v + 3 = 2v + 6 and -(2v + 3) = 2v + 6

The first equation has no real solutions

For the second, we have

-2v - 3 = 2v + 6 subtract 2v from both sides and add 3 to both sides

-4v = 9 divide both sides by -4

v = -9/4 = -2.25

Here's a graph of the solution using "x" imstead of "v"...... https://www.desmos.com/calculator/zdbtixc1np

CPhill
Sep 15, 2014