Take both things out of the absolute value bars and solve two equations
2v + 3 = 2v + 6 and -(2v + 3) = 2v + 6
The first equation has no real solutions
For the second, we have
-2v - 3 = 2v + 6 subtract 2v from both sides and add 3 to both sides
-4v = 9 divide both sides by -4
v = -9/4 = -2.25
Here's a graph of the solution using "x" imstead of "v"...... https://www.desmos.com/calculator/zdbtixc1np
Take both things out of the absolute value bars and solve two equations
2v + 3 = 2v + 6 and -(2v + 3) = 2v + 6
The first equation has no real solutions
For the second, we have
-2v - 3 = 2v + 6 subtract 2v from both sides and add 3 to both sides
-4v = 9 divide both sides by -4
v = -9/4 = -2.25
Here's a graph of the solution using "x" imstead of "v"...... https://www.desmos.com/calculator/zdbtixc1np