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# Abs(2v+3)=Abs(2v+6)

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Abs(2v+3)=Abs(2v+6)

Guest Sep 15, 2014

#1
+85727
+5

Take both things out of the absolute value bars and solve two equations

2v + 3  = 2v + 6         and        -(2v + 3) = 2v + 6

The first equation has no real solutions

For the second, we have

-2v - 3  = 2v + 6           subtract 2v from both sides and add 3 to both sides

-4v = 9                         divide both sides by -4

v  = -9/4   = -2.25

Here's a graph of the solution using "x" imstead of "v"......  https://www.desmos.com/calculator/zdbtixc1np

CPhill  Sep 15, 2014
Sort:

#1
+85727
+5

Take both things out of the absolute value bars and solve two equations

2v + 3  = 2v + 6         and        -(2v + 3) = 2v + 6

The first equation has no real solutions

For the second, we have

-2v - 3  = 2v + 6           subtract 2v from both sides and add 3 to both sides

-4v = 9                         divide both sides by -4

v  = -9/4   = -2.25

Here's a graph of the solution using "x" imstead of "v"......  https://www.desmos.com/calculator/zdbtixc1np

CPhill  Sep 15, 2014

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