#1**+3 **

I expect you are over thinking it.

if a+b+c=0 and none are 0 (and all are reak) then one must be neg, one pos and the other either one.

So when you multiply them together the answer could be positive or negative

a/|a|= plus or minus 1 etc

so maybe you are looking for all the possible combinations of

\(\pm 1\pm1\pm1\pm1\)

Or maybe you can discount some of those answers off. Think about it a bit.

Anyway, I know someone else is also answering this right now.

Melody Jun 3, 2021

#2**+3 **

There are 2 cases for this (negative, negative, positive) or (positive, positive, negative).

For this problem, order doesn't matter.

**negative, negative, positive**

a and b are negative, and c is positive.

a/|a| would be -1 since a is negative.

b/|b| would be -1 since b is negative.

c/|c| would be 1 since c is positive.

abc/|abc| would be 1, since negative * negative * positive is positive.

-1 - 1 + 1 + 1 = 0

**positive, positive, negative**

a and b are positive, and c is negative.

a/|a| would be 1 since a is positive.

b/|b| would be 1 since b is positive.

c/|c| would be -1 since c is negative.

abc/|abc| would be -1, since positive * positive * negative is negative.

1 + 1 - 1 - 1 = 0

So I think there is only one value, 0.

=^._.^=

catmg Jun 3, 2021