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When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

 Jan 7, 2016

Best Answer 

 #2
avatar
+10

3x^2-2y = 3 (9) - 10 = 17

2x^2-3y = 2(9) -15   = 3

 

17 -3 = 14         14

 Jan 7, 2016
 #1
avatar+2498 
+4

332-25 = 307 

232-35 = 197

307-197=110

 Jan 7, 2016
 #2
avatar
+10
Best Answer

3x^2-2y = 3 (9) - 10 = 17

2x^2-3y = 2(9) -15   = 3

 

17 -3 = 14         14

Guest Jan 7, 2016
 #3
avatar+2498 
+4

there is a lot of posibilities you wrote smth wrong

 Jan 7, 2016
 #4
avatar+118677 
+10

Thanks Guest, Solveit this question really confused you, i expect that you had some problems with the English. :)

 

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

 

\(When\; x=3\; and \;y=5\\ 3x^2-2y=3*9-10=27-10=17\\ and\\ 2x^2-3y=2*9-15=18-15=3\)

 

So the question becomes

By how much does 17 exceed 3

 

The answer is 17-3=14

 Jan 8, 2016

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