ACT prep

Question

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When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

Guest Jan 7, 2016

+10

Best Answer

3x^2-2y = 3 (9) - 10 = 17

2x^2-3y = 2(9) -15 = 3

17 -3 = 14 14

Guest Jan 7, 2016

Guest · Answer 1 · 2016-01-07T03:44:03

3x^2-2y = 3 (9) - 10 = 17

2x^2-3y = 2(9) -15 = 3

17 -3 = 14 14

Solveit · Answer 2 · 2016-01-07T03:39:32

332-25 = 307

232-35 = 197

307-197=110

Solveit · Answer 3 · 2016-01-07T03:46:28

there is a lot of posibilities you wrote smth wrong

Melody · Answer 4 · 2016-01-08T09:23:37

Thanks Guest, Solveit this question really confused you, i expect that you had some problems with the English. :)

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

$When\; x=3\; and \;y=5\\ 3x^2-2y=3*9-10=27-10=17\\ and\\ 2x^2-3y=2*9-15=18-15=3$

So the question becomes

By how much does 17 exceed 3

The answer is 17-3=14