In a candybag there is 50 candycars. White, Green and pink. You take 2 of them. How many candycars of the certain colors are there if the probability to take 2 green ones with reversal is 0,25 and to take 2 pink ones is 0,09?
+118653 In a candybag there is 50 candycars. White, Green and pink. You take 2 of them. How many candycars of the certain colors are there if the probability to take 2 green ones with reversal is 0,25 and to take 2 pink ones is 0,09?
I think that you have English as a second language so I will take the liberty of rewording your question:
In a candybag there is 50 candycars. White, Green and pink. You take 2 of them. How many candycars of the certain colors are there if the probability to take 2 green ones with replacement is 0.25 and to take 2 pink ones is 0.09?
\(\frac{G}{50}*\frac{G}{50}=\frac{1}{4}\\ \frac{G}{50}=\frac{1}{2}\qquad \text{I took the square root of both sides}\\ G=25\\~\\ (\frac{P}{50})^2=\frac{9}{100}\\ \frac{P}{50}=\frac{3}{10}\\ P=15\\~\\ W=50-25-15=10\)
So there are 25 green, 15 Pink and 10 white candies :)
