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A rectangle has a length of x and a width of 5x3 + 4 - x2 . Find the perimeter of the rectangle when the length is 5 feet.

Guest Oct 25, 2018
edited by Guest  Oct 25, 2018
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Since I do not know if by x2 you meant \(2x\) or \(x^2\), I'll solve for both.

 

Okay. here is the solution for when it is \(2x\):

 

If the length is 5ft, then \(x = 5\).

 

Using this to solve for \(5x^3 + 4 - 2x\), we get \(625 + 4 - 10 = 619\).

 

The perimeter is \(5 + 5 + 619 + 619 = \boxed{1248}\) ft.

 

Now, here is the solution for when it is \(x^2\).

 

If the length is 5ft, then \(x = 5\).

 

Using this to solve for \(5x^3 + 4 - x^2\), we get \(625 + 4 - 25 = 604\).

 

The perimeter is \(5 + 5 + 604 + 604 = \boxed{1218}\) ft. 

KnockOut  Oct 26, 2018

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