We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

A rectangle has a length of x and a width of 5x^{3} + 4 - x2 . Find the perimeter of the rectangle when the length is 5 feet.

Guest Oct 25, 2018

edited by
Guest
Oct 25, 2018

#1**+16 **

Since I do not know if by x2 you meant \(2x\) or \(x^2\), I'll solve for both.

Okay. here is the solution for when it is \(2x\):

If the length is 5ft, then \(x = 5\).

Using this to solve for \(5x^3 + 4 - 2x\), we get \(625 + 4 - 10 = 619\).

The perimeter is \(5 + 5 + 619 + 619 = \boxed{1248}\) ft.

Now, here is the solution for when it is \(x^2\).

If the length is 5ft, then \(x = 5\).

Using this to solve for \(5x^3 + 4 - x^2\), we get \(625 + 4 - 25 = 604\).

The perimeter is \(5 + 5 + 604 + 604 = \boxed{1218}\) ft.

KnockOut Oct 26, 2018