After blast off, a space shuttle climbs vertically and a radar tracking dish, located 1000 yd from the launch pad, follows the shuttle. How fast is the radar dish revolving 10 sec after blast-off if at the time the velocity of the shuttle is 100 yd/sec and the shuttle is 500 yd above the ground?
This is my best guess
When t=10sec y=500yards and dy/dt=100 yards/sec and θ=atan(5001000)=atan(0.5)
tanθ=y1000y=1000tanθdydθ=1000sec2θdθdy=cos2θ1000dθdt=dθdy×dydtWhent=10dθdt=cos2θ1000×100dθdt=cos2(atan(0.5))10dθdt=45÷10dθdt=450dθdt=225radians/sec |
I think that this is correct.
This is my best guess
When t=10sec y=500yards and dy/dt=100 yards/sec and θ=atan(5001000)=atan(0.5)
tanθ=y1000y=1000tanθdydθ=1000sec2θdθdy=cos2θ1000dθdt=dθdy×dydtWhent=10dθdt=cos2θ1000×100dθdt=cos2(atan(0.5))10dθdt=45÷10dθdt=450dθdt=225radians/sec |
I think that this is correct.