+0

# Again #2

0
400
6
+65

A mother is 34 years old, and her son is 6 yers old. How old will her son be, if her mother gets two times older than her?

(Explanation will be nice)

May 10, 2016

#4
+5

34 - 6 = 28 years - mother's age when her son was born.

28 x 2 =56 mother's age when her son will be 28, or half her age.

Guys-Remember Occam's Razor Principle!.

May 10, 2016

#1
+18274
+5

34 = mothers age

6 = son's age

in 'x' years mom will be 34 + x     son will be 6+x    ALSO   two times sons age is equal to mom's    34+x = 2(6+x)   solve for x = 22 years

so sone will be 6 + 22 = 28 and mom will be  34 + 22 = 56

May 10, 2016
#2
+101088
+5

Let y be the number of years until the mother is twice as old.....so we have......

The mother's age at that time   =  2 times the son's age at that time

34 +  y   =  2 ( 6 + y)    simplify

34 + y =  12  + 2y     subtract y, 12 from both sides

22  = y

The mother will be twice as old in 22 more years

And in 22 years, the son  will be 6 + 22  = 28 years old

Check :

34 + 22  =  56

6 + 22  =  28

And 56  is twice as old as 28   !!!!

May 10, 2016
#3
+65
0

Thanks to both of you!

May 10, 2016
#4
+5

34 - 6 = 28 years - mother's age when her son was born.

28 x 2 =56 mother's age when her son will be 28, or half her age.

Guys-Remember Occam's Razor Principle!.

Guest May 10, 2016
#5
+18274
0

Ha!   Good one 'Guest' !

ElectricPavlov  May 10, 2016