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avatar+65 

A mother is 34 years old, and her son is 6 yers old. How old will her son be, if her mother gets two times older than her?

(Explanation will be nice)

Lunar  May 10, 2016

Best Answer 

 #4
avatar
+5

34 - 6 = 28 years - mother's age when her son was born.

28 x 2 =56 mother's age when her son will be 28, or half her age.

Guys-Remember Occam's Razor Principle!.

Guest May 10, 2016
 #1
avatar+13590 
+5

34 = mothers age

6 = son's age   

 

 

in 'x' years mom will be 34 + x     son will be 6+x    ALSO   two times sons age is equal to mom's    34+x = 2(6+x)   solve for x = 22 years  

so sone will be 6 + 22 = 28 and mom will be  34 + 22 = 56

ElectricPavlov  May 10, 2016
 #2
avatar+91027 
+5

Let y be the number of years until the mother is twice as old.....so we have......

 

The mother's age at that time   =  2 times the son's age at that time

 

34 +  y   =  2 ( 6 + y)    simplify

 

34 + y =  12  + 2y     subtract y, 12 from both sides

 

22  = y

 

The mother will be twice as old in 22 more years

 

And in 22 years, the son  will be 6 + 22  = 28 years old

 

Check :

 

34 + 22  =  56

 

6 + 22  =  28

 

And 56  is twice as old as 28   !!!!

 

 

 

cool cool cool

CPhill  May 10, 2016
 #3
avatar+65 
0

Thanks to both of you!

Lunar  May 10, 2016
 #4
avatar
+5
Best Answer

34 - 6 = 28 years - mother's age when her son was born.

28 x 2 =56 mother's age when her son will be 28, or half her age.

Guys-Remember Occam's Razor Principle!.

Guest May 10, 2016
 #5
avatar+13590 
0

Ha!   Good one 'Guest' !

ElectricPavlov  May 10, 2016

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