+157 A motorcycle is depreciating at 12% per year, every year. A student's $11,250 motorcycle depreciating at this rate can be modeled by the equation V(t) = 11,250(0.88)^t. What is an equivalent equation for this vehicle as a monthly depreciation and, using this equation, what is the motorcycle worth (rounded to the nearest hundred dollar) 8 years after purchase?
A. V(t) = 11,250(0.9894)^12t, $4,000
B. V(t) = 11,250(0.8800)^12t, $10,300
C. V(t) = 11,250(1.12)^−t, $4,500
D. V(t) = 11,250(0.9894)^t, $4,000
+2592 No algebra needed here. Just good question skills
B is wrong do to amount left, 10300 is way too high for 12% per year
C has a negative exponet
D has only 1 exponet as opposed to the 12 that is needs.
So correct anwser is A
+2592 No algebra needed here. Just good question skills
B is wrong do to amount left, 10300 is way too high for 12% per year
C has a negative exponet
D has only 1 exponet as opposed to the 12 that is needs.
So correct anwser is A
+129849 We need to find the effective rate of monthly depreciation......we can do this,as follows :
(.88)^8 = (r)^(12*8)
(.88)^8 = r^(96) take the log of both sides
log(.88)^8 = log (r)^96 and we can write
8log(.88) = 96 log (r) divide both sides by 96
(1/12) log(.88) = log r
This says that
10^[(1/12) log(.88)] = r = about .9894
So.....A would be correct, as Spawn said
