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# Alex bought some cherries at \$5 per pound and some oranges at \$2 per pound. If he paid \$18 for the cherries and oranges combined, and if the

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Alex bought some cherries at \$5 per pound and some oranges at \$2 per pound. If he paid \$18 for the cherries and oranges combined, and if the total weight of the cherries and oranges was 6 pounds, how many pounds of cherries did Alex buy?

math algebra
Guest Aug 13, 2014

#1
+85789
+10

Let x be the weight of the cherries

Then (6-x) must be the weight of the oranges...since, together, they weigh 6 lbs.

So we have.....

(The weight of the cherries times their cost per pound) + (the weight of the oranges times their cost per pound) = (the total cost)     ....or......mathematically.....

x(5) + (6-x)(2) = 18   ....simplifyting, we get

5x + 12 - 2x  = 18       ......simplify again

3x + 12 = 18                ....subtract 12 from both sides

3x = 6

x = 2 lbs. of cherries

CPhill  Aug 13, 2014
Sort:

#1
+85789
+10

Let x be the weight of the cherries

Then (6-x) must be the weight of the oranges...since, together, they weigh 6 lbs.

So we have.....

(The weight of the cherries times their cost per pound) + (the weight of the oranges times their cost per pound) = (the total cost)     ....or......mathematically.....

x(5) + (6-x)(2) = 18   ....simplifyting, we get

5x + 12 - 2x  = 18       ......simplify again

3x + 12 = 18                ....subtract 12 from both sides

3x = 6

x = 2 lbs. of cherries

CPhill  Aug 13, 2014

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