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algebra 1

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what is the value of x in the equation (8x)[(2x)]^2=8

Guest Apr 18, 2017
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8x(2x)^2=8

Divide both sides by 8

x(2x)^2=1

Simplify the exponent

x(2x)^2=x(2x)(2x)

Apply the distributive property

(2x)(2x)=4x^2

(4x^2)x=4x^3

We now have 4x^3=1

Divide by the constant on the left side (4)

x^3=(1/4)

Take the cube root

$$x = \sqrt[3]{1/4}$$

Simplify

$$x = 1/\sqrt[3]{4}$$

bingby  Apr 18, 2017

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