Algebra 2 help!!!!!

Here is option one:

 

f(x)  =  (x - 1)(x - 3)(x - 5)  =  (x - 1)(x² - 8x + 15)  =  x³ - 9x² + 23x - 15

 

f(x)  =  x³ - 9x² + 23x - 15

 

We can multiply the previous polynomial by any number and the resulting polynomial will have the same zeros....I picked  -2. Here is option two:

 

f(x)  =  -2(x - 1)(x - 3)(x - 5)  =  -2(x³ - 9x² + 23x - 15)  =  -2x³ + 18x² - 46x + 30

 

f(x)  =  -2x³ + 18x² - 46x + 30

 

Here's a graph with these two functions on it:   https://www.desmos.com/calculator/lmrqxh79cx