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Algebra 2 help!!!!!!!!

 Oct 3, 2017
 #1
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Here is option one:

 

f(x)  =  (x - 1)(x - 3)(x - 5)  =  (x - 1)(x2 - 8x + 15)  =  x3 - 9x2 + 23x - 15

 

f(x)  =  x3 - 9x2 + 23x - 15

 

We can multiply the previous polynomial by any number and the resulting polynomial will have the same zeros....I picked  -2. Here is option two:

 

f(x)  =  -2(x - 1)(x - 3)(x - 5)  =  -2(x3 - 9x2 + 23x - 15)  =  -2x3 + 18x2 - 46x + 30

 

f(x)  =  -2x3 + 18x2 - 46x + 30

 

Here's a graph with these two functions on it:   https://www.desmos.com/calculator/lmrqxh79cx

 Oct 3, 2017

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