+18 Problem: If \(log{}_{2}x=7\),find \(log{}_{8}x.\)
I am not allowed to use a calculator on this problem.
These are steps I have so far:
27=x
x=128
log8128=y
8y=128
y=\(\frac{log 128}{log 8}\)
And this is where I am stuck. I have to use a calculator for this part. Is there a way to solve this without using a calculator?
Thanks.
+526 So far, you're doing really well..
After \(y = {log128\over log8}\) you don't really need a calculator to solve this
We can write this as
\(y= {log 2^7\over log 2^3}\) right?
then \(y= {7log2\over 3log2}\)
⇒\(y={7\over 3}\)
\({log}_{8}x = {7\over 3}\)
Hope you got it :)
+18 Oh yea you can write it like that then use the log rules and division. Thanks for the help!
