+0  
 
0
82
9
avatar+84 

deleted

 Apr 15, 2020
edited by VVoidSmiley69  May 27, 2020

Best Answer 

 #9
avatar
0

Have you noticed that there are at least 13 posts asking this question? (There are more, but these have answers.)

 

https://web2.0calc.com/questions/a-parabola-with-equation-y-ax-2-bx-c-has-a-vertical-line-of-symmetry-at-x-2-and-goes-through-the-two-points-1-1-and-4-1-the-quadratic-ax-2-bx
https://web2.0calc.com/questions/help-me-please_130
https://web2.0calc.com/questions/please-help_11649
https://web2.0calc.com/questions/help-plz_44287
https://web2.0calc.com/questions/need-help-by-the-end-of-today
https://web2.0calc.com/questions/help-plz_5023
https://web2.0calc.com/questions/urgently-need-help-within-two-days
https://web2.0calc.com/questions/quick-math-question_7
https://web2.0calc.com/questions/math_34788
https://web2.0calc.com/questions/math-help_2416
https://web2.0calc.com/questions/a-quadratic-of-the-form-2x-2-bx-c-has-roots-of-x
https://web2.0calc.com/questions/help_27016
https://web2.0calc.com/questions/algebra-2-parabolas-please-help

 

I know you're trying to help, but these people don't even search for existing answers. This shows how little effort they're putting into their math. :-(

 

As many other questions in this site, this is an AoPS question. AoPS students have a live class, where they learn from an instructor and the class is highly interactive. If you don't understand, then you can ask and there are people ready to help in real time. The online materials for the class are always available for the duration of the course.

 

Even if you can't make it to the class, you can see what happened later, as there's a transcript of each session. If you're working on your homework and have questions, AoPS also has a forum that is available 24/7. Lots of people are ready to help there. The website is well designed even for use with smartphones, so wherever you go, you get access to all of this. A student can receive hints on how to proceed. When they show some work, they get tailored replies depending on what's the part they're finding hard to understand.

 

Most students asking AoPS questions here are only looking for a cheap way out.

 Apr 21, 2020
 #1
avatar+23552 
+1

See this first

https://web2.0calc.com/questions/question_65419

 

then we need to modify it by multiplying by -2

 

(x^2 - 6x + 4 ) x (-2) = -2x^2 +12x - 8        Vertex will be at  x = - b/2a =  - 12 / (2*-2) = 3

 

The use this value of x to find the 'y' value by substituting into the equation   y = .........

 Apr 15, 2020
 #2
avatar
0

If the question is asking for the vertex, does that mean 'x' is 3, and we have to subsitute x for 3, to find out y?

Guest Apr 16, 2020
 #3
avatar
0

Also, the vertex is x=-b/2a, and a is -2... shouldn't it be -3, not 3?

Guest Apr 16, 2020
 #4
avatar+109492 
0

Attn:  WoidSmiley69

 

It is time for you to start presenting your questions properly.

 

I would be interested in looking at this one if it was not presented so poorly.

 Apr 17, 2020
edited by Melody  Apr 17, 2020
 #5
avatar
+1

Here Melody, I think that is what he meant:

"A quadratic of the form \(-2x^2+bx+c\) has roots of \(x=3+\sqrt{5}\) and \(x=3-\sqrt{5}\) .

The graph of \(y=-2x^2+bx+c\) a parabola. Find the vertex of this parabola."

Guest Apr 17, 2020
 #6
avatar+109492 
0

Thanks guest,

 

Yes I know that is what he means but I have to rewrite the question properly before I can think it through.

I just cannot look at those dollar signs and ignore them, I have to physically remove them before I start on the problem.

I'm just not prepared to do that.

 

If they are too lazy to post their questions the best possible, then I expect they will be far too lazy to learn from any response.

Melody  Apr 17, 2020
 #7
avatar+84 
+2

Sorry I am new to Latex, I will try not to do it again :)

VVoidSmiley69  Apr 19, 2020
 #8
avatar+109492 
0

ok, if you entered it into the LaTex box, all you probably needed to do was delete the dollar signs. 

 

Play around with it for a bit and you will work it out.

Melody  Apr 21, 2020
 #9
avatar
0
Best Answer

Have you noticed that there are at least 13 posts asking this question? (There are more, but these have answers.)

 

https://web2.0calc.com/questions/a-parabola-with-equation-y-ax-2-bx-c-has-a-vertical-line-of-symmetry-at-x-2-and-goes-through-the-two-points-1-1-and-4-1-the-quadratic-ax-2-bx
https://web2.0calc.com/questions/help-me-please_130
https://web2.0calc.com/questions/please-help_11649
https://web2.0calc.com/questions/help-plz_44287
https://web2.0calc.com/questions/need-help-by-the-end-of-today
https://web2.0calc.com/questions/help-plz_5023
https://web2.0calc.com/questions/urgently-need-help-within-two-days
https://web2.0calc.com/questions/quick-math-question_7
https://web2.0calc.com/questions/math_34788
https://web2.0calc.com/questions/math-help_2416
https://web2.0calc.com/questions/a-quadratic-of-the-form-2x-2-bx-c-has-roots-of-x
https://web2.0calc.com/questions/help_27016
https://web2.0calc.com/questions/algebra-2-parabolas-please-help

 

I know you're trying to help, but these people don't even search for existing answers. This shows how little effort they're putting into their math. :-(

 

As many other questions in this site, this is an AoPS question. AoPS students have a live class, where they learn from an instructor and the class is highly interactive. If you don't understand, then you can ask and there are people ready to help in real time. The online materials for the class are always available for the duration of the course.

 

Even if you can't make it to the class, you can see what happened later, as there's a transcript of each session. If you're working on your homework and have questions, AoPS also has a forum that is available 24/7. Lots of people are ready to help there. The website is well designed even for use with smartphones, so wherever you go, you get access to all of this. A student can receive hints on how to proceed. When they show some work, they get tailored replies depending on what's the part they're finding hard to understand.

 

Most students asking AoPS questions here are only looking for a cheap way out.

Guest Apr 21, 2020

21 Online Users

avatar