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When g(x) is divided by x^2-x-6, the remainder is x+5. What is the value of g(3)?

 

thank you!

 Feb 2, 2022
 #1
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Let g(x) =  p(x)*(x2-x-6) + R(x)   where p(x) is some other polynomial and R(x)= x + 5.

 

When x = 3   g(3) = p(3)*(3^2-3-6) + (3+5)   ie  x^2-x-6 = 0, so all that is left of g(3) is 3 + 5.  i.e. g(3) = 8.

 Feb 3, 2022
 #2
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thank you for your solution!

Guest Feb 3, 2022

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