Algebra 2: Vertex and Axis of Symmetry

y=-1x^2+2x       

In the form   y = ax^2 + bx + c  ......the x coordinate of the vertex is given by:

x =  -b / 2a        and here    b = 2 and a = -1

So.....the x coordinate of the vertex =    -2 / [2* -1]  = -2/-2   = 1

And puting the x coordinate of the vertex back into the function to find the y coordinate of the vertex, we have :  -1(1)^2 + 2(1)   = -1 + 2 = 1

So....the vertex =  (1,1)

And the axis of symmetry is given by x  = [the x coordinate of the vertex]  

So.....the axis of symmetry is :

x =  1