Not maybe the fastest way....but.....pick a point in the feasible region ....let's say....(2,0)
Look at the first system.....
3(2) + 5(0) ≤ 10
6 + 0 ≤ 10 true
-2 + 0 > -5 true
0 - 6 > 5(-2)
-6 > -10 true
So....the point makes all three true....so....this system is the correct one
BTW, Cupcake......another way is to graph these inequalities and see which look like the given graph....do you know how to do this???
I find Desmos helpful....!!!!