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# algebra 2

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The real numbers x, y and z satisfy the equations x+2y+3z=950 and 3x+2y+z=1450. What is the average of x, y and z?

Sep 4, 2022

$$\text{Add the two equations together to get }$$$$4(x+y+z)=2400, \text{thus } x+y+z=600.$$$$\text{ Because we have 3 numbers, we divide}$$$$\text{this by 3 to get the average:} \frac{x+y+z}{3}=\boxed{200.}$$