+0

# Algebra 2

0
162
1

Given V = 2πr2h, solve for h

A)h = V/2r2

B)h = V2πr2

C)h = V - 2πr2

D)h = V/2πr2

f(x) = x2 - 5

For the function shown, what is the range of the function when the domain is {2, 4, 7}?

A){-1, 44}

B){-1, -5}

C){6, 21, 54}

D){-1, 11, 44}

Guest Aug 15, 2017
Sort:

#1
+1961
+1

1)

When the question asks to solve for in the equation of $$V=2\pi r^2h$$, it means get h, alone, on one side of the equation.  This only requires one step, in this case:

 $$V=2\pi r^2h$$ Divide by $$2\pi r^2$$ on both sides of the equation. $$h=\frac{V}{2\pi r^2}$$ We're done! h is by itself.

The appropriate answer choice, therefore, is D

2) If the domain is only {2, 4, 7}, just plug them in the original equation of $$f(x)=x^2-5$$.

 $$f(2)=2^2-5=-1$$ $$f(4)=4^2-5=11$$ $$f(7)=7^2-5=44$$

Now, find the answer choice that has all three of these in its domain. That would be D again.

TheXSquaredFactor  Aug 15, 2017