+0  
 
0
44
1
avatar

Given V = 2πr2h, solve for h

 

A)h = V/2r2

B)h = V2πr2

C)h = V - 2πr2

D)h = V/2πr2

 

 

f(x) = x2 - 5

For the function shown, what is the range of the function when the domain is {2, 4, 7}?

 

A){-1, 44}

B){-1, -5}

C){6, 21, 54}

D){-1, 11, 44}

Guest Aug 15, 2017
Sort: 

1+0 Answers

 #1
avatar+1107 
+1

1)

 

When the question asks to solve for in the equation of \(V=2\pi r^2h\), it means get h, alone, on one side of the equation.  This only requires one step, in this case:

 

\(V=2\pi r^2h\) Divide by \(2\pi r^2\) on both sides of the equation.
\(h=\frac{V}{2\pi r^2}\) We're done! is by itself.
   

 

The appropriate answer choice, therefore, is D

 

2) If the domain is only {2, 4, 7}, just plug them in the original equation of \(f(x)=x^2-5\).

 

\(f(2)=2^2-5=-1\)  
\(f(4)=4^2-5=11\)  
\(f(7)=7^2-5=44\)  
   

 

Now, find the answer choice that has all three of these in its domain. That would be D again.

TheXSquaredFactor  Aug 15, 2017

16 Online Users

avatar
avatar
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  See details