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# Algebra advanced systems of equations

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Can someone help me?

Amy, Ben, Carl, and Debbie each have some coins. Ben has three times the number of coins that Amy has and a third of the number of coins that Carl has, and Debbie has two-thirds the number of coins that Carl has. The number of coins that Amy has, multiplied by the number of coins that Ben has, multiplied by the number of coins that Carl has, multiplied by the number of coins that Debbie has, is 162 . How many coins do the four children have all together?

That is the question.

Aug 31, 2020
edited by Jmaster10  Sep 1, 2020

#1
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Amy, Ben, Carl, and Debbie each have some coins. Ben has three times the number of coins that Amy has and a third of the number of coins that Carl has, and Debbie has two-thirds the number of coins that Carl has. The number of coins that Amy has, multiplied by the number of coins that Ben has, multiplied by the number of coins that Carl has, multiplied by the number of coins that Debbie has, is . How many coins do the four children have all together?

So, this is an extremely long problem, and hence we must turn it into words.

A = Amy

B = Ben

C= Carl

D= Debbie

B = 3A

3B = C

3D = 2C

ABCD = NOT STATED

A+B+C+D = x (we want x)

Please state what them all multiplied together is.

Aug 31, 2020
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ABCD = 162

Jmaster10  Sep 1, 2020