+216 Can someone please help?
Amy, Ben, Carl, and Debbie each have some coins. Ben has three times the number of coins that Amy has and a third of the number of coins that Carl has, and Debbie has two-thirds the number of coins that Carl has. The number of coins that Amy has, multiplied by the number of coins that Ben has, multiplied by the number of coins that Carl has, multiplied by the number of coins that Debbie has, is 162. How many coins do the four children have all together?
That is my question.
+1084 @ SHADOWwolf, don't you see that the link brings you back to the same page? What is the point of the link if it only brings you to the same page? Who are you trying to help? Are you just a troll that asks questions and clogs up the forum with "not so useful" links and answers like my hair clogs the bathroom drain? Or is it the wrong link? (The preview is there for a reason)
Anyways, for your question we will need variables:
A = Amy's coins
B = Ben's coins
C= Carl's coins
D= Debbie's coins
With what we know, we can say this:
B = 3A
3B = C
3D = 2C
ABCD = 162
First and foremost, we need to write each variable in terms of one variable. Let's use A:
A = A
B = 3A
C = 3B = 3(3A) = 9A
D = 2/3C = 6A
Therefore:
ABCD = A (3A) (9A) (6A) = 162A^4 = 162
A = 1
Now that we know that A is 1, we can say that:
A = 1
B = 3(1) = 3
C = 9(1) = 9
D = 6(1) = 6
To check the work, let's multiply:
1 * 3 * 9 * 6 = 162.
so our answer is right.
:)
+42 When I use the link it takes me to a page where the question has already been answered. Sorry if you can't see it.
