+0

# algebra b help

0
71
1
+79

what is the least value of $$y$$ such that $$3y^2 + 5y + 2 = 4$$?

Jan 19, 2020

#1
0

Solve by factoring the quadratic equation or by applying the quadratic formula.

$$3y^2+5y-2=0$$ (I.e. just subtracted 4 from both sides so the right hand side is = 0)

factor

$$(3y-1)(y+2)=0$$

so

$$y=-2$$

y=$$\frac{1}{3}$$

"Least value of y" so y=$$\frac{1}{3}$$ is the answer.

Jan 19, 2020