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what is the least value of \(y\) such that \(3y^2 + 5y + 2 = 4 \)?

 Jan 19, 2020
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Solve by factoring the quadratic equation or by applying the quadratic formula.

 

\(3y^2+5y-2=0\) (I.e. just subtracted 4 from both sides so the right hand side is = 0) 

factor

\((3y-1)(y+2)=0\)

so

\(y=-2\)

y=\(\frac{1}{3}\)

"Least value of y" so y=\(\frac{1}{3}\) is the answer.

 Jan 19, 2020

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