What real value of \(t\) produces the smallest value of the quadratic \(t^2 -9t - 36 \)?
Use the factoring method to get -3 as the answer for t.
The "t" that produces the smallest value is at the vertex of this parabola.....this is
- (-9) / [ -2 *1 ] = 9/2 = 4.5
See the graph here : (I've used x instead of t....but....same idea) :