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Which graph represents the exponential function𝑓(𝑥) = 2(2)x-4 ? 

Guest Dec 1, 2017

Best Answer 

 #2
avatar+7155 
+1

Maybe it is supposed to be

 

f(x)  =  2(2)x - 4        ???

 

If so...

 

f(0)   =   2(2)0 - 4   =   2(1) - 4   =   2 - 4   =   -2     So the graph passes through  (0, -2) .

 

f(1)   =   2(2)1 - 4   =   2(2) - 4   =   4 - 4   =   0     So the graph passes through  (1, 0) .

 

The first graph passes through  (0, -2)  and  (1, 0)  , so it looks right.

 

Here's a graph of  y = 2(2)x - 4

hectictar  Dec 1, 2017
 #1
avatar+87569 
+1

None of them

 

Here is the graph  :  https://www.desmos.com/calculator/6t93qupx9m

 

Are you sure that you have the correct function ???

 

 

cool cool cool

CPhill  Dec 1, 2017
 #2
avatar+7155 
+1
Best Answer

Maybe it is supposed to be

 

f(x)  =  2(2)x - 4        ???

 

If so...

 

f(0)   =   2(2)0 - 4   =   2(1) - 4   =   2 - 4   =   -2     So the graph passes through  (0, -2) .

 

f(1)   =   2(2)1 - 4   =   2(2) - 4   =   4 - 4   =   0     So the graph passes through  (1, 0) .

 

The first graph passes through  (0, -2)  and  (1, 0)  , so it looks right.

 

Here's a graph of  y = 2(2)x - 4

hectictar  Dec 1, 2017
 #3
avatar+87569 
+1

Nice detective work, hectictar.....!!!!

 

 

cool cool cool

CPhill  Dec 1, 2017

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