One ordered pair (a,b) satisfies the two equations ab^4 = 384 and ab^5 = 4608. What is the value of a in this ordered pair?
+240 ab^5 is basically ab^4 * b. Plugging in known values and simplifying,
\(ab^5 = ab^4 \cdot b\)
\(4608 = 384\cdot b\)
\(b = 12\)
Plug b into one of the known equations,
\(a \cdot 12^4 = 384\)
\(a \cdot 20736 = 384\)
\(a = 1/54\)
So the value of a is 1/54.
