+5265 The area A of a rectangle with a perimeter of 32 cm is modeled as -x2+16x, where x is the width in cm. What is that maximum area of the rectangle?
+37146 -x^2 +16x = 32
-x^2 + 16x - 32 = 0
This is a parabola, with the maximum at x=8
-(8^2)+16(8) = 64 cm^2 maximum area
+257 try it in the calculater the nimber you just gave me and tell me what you get ok then we will go on from there alright
+5265 It's not asking to substitute the perimeter. It's asking what the maximum area could be for that rectangle.
+37146 -x^2 +16x = 32
-x^2 + 16x - 32 = 0
This is a parabola, with the maximum at x=8
-(8^2)+16(8) = 64 cm^2 maximum area
+37146 Maybe easier:
-x^2 +16x is a parabola with a maximum value of 64 at x= 8
+37146
ERROR though it gives the correct answer
ignore my -x^2+16 = 32 answer it is incorrect
use the -x^2+16 is a parabola answer max value = 64 at x = 8
