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avatar+115 

OK, so im pretty sure this is really ez except im kinda confusioned rn.

\(Simplify: \frac{(\frac{1}{y}-\frac{1}{x})}{\frac{1}{y}+\frac{1}{x}} \)

 May 16, 2021
 #1
avatar+544 
+2

\(\frac{(\frac{1}{y} - \frac{1}{x})}{\frac{1}{y} + \frac{1}{x}}\)

\(= \frac{\frac{x - y}{xy}}{\frac{x+y}{xy}}\)

\(= \frac{x-y}{x+y}\)

 

I think this is right..

 May 16, 2021
 #2
avatar+113625 
+1

Logarythm:

Your answer looks good to me    wink

 

Except ....

you forgot to mention the restriction

x and y are real numbers such  that

x is not equal to 0   and

y is not equal to 0 and

x is not equal to -y

Melody  May 16, 2021
edited by Melody  May 16, 2021

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