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# Algebra plz help

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1. The graph of y = h(x) is shown in red below. Compute h(h(7)). (Assume grid lines are spaced 1 unit apart.)

2. Below is a portion of the graph of a function, y=u(x): What is the exact value of u(-2.72)+u(-0.81)+u(0.81)+u(2.72) ?

Mar 4, 2019

#1
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1.   h(7)  means that we go to 7 on  x and look at the y value at that point...this is 5

So   h(7) = 5

So...now we are trying to find h(h(7)) = h(5)

So now...we do the same thing.....go to  5 on x  and find the y value at that point = this is -1

So   h(h(7)) = h(5)  =   -1       !!!   Mar 4, 2019
#2
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2. This one seems harder than it really is

This function is odd [ it is symmetric about the orgin ] which means that if   ( - a, - b)  is on the graph....then so is (a, b)

So  u (-2.72)  leads to some - b

And u (2.72) leads to some b

So adding these together, we get  -b + b = 0

The same logic will apply to u(-0.81)  and u(0.81)

Adding their outputs will = 0

So

u(-2.72)+u(-0.81)+u(0.81)+u(2.72)  =    0   Mar 4, 2019