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Five workers have been hired to complete a job. If one additional worker is hired, they could complete the job $8$ days earlier. If the job needs to completed $28$ days earlier, how many additional workers should be hired?

 Aug 31, 2023

Best Answer 

 #1
avatar+37147 
+1

x = worker days needed to complete the job

x/5  =  days for 5 to complete 

x/(5+1) = x/5 - 8     

x/6 = x/5 - 8 

5x/30 - 6x/30 = - 8

     solve for x = 240 worker days 

 

Now for 28 days less:

240/ ( 5 + n) =  240/5 -28      where n = number of additional workers

240/(5+n) = 20 

n = 7 additional workers needed above the original 5 

 Aug 31, 2023
 #1
avatar+37147 
+1
Best Answer

x = worker days needed to complete the job

x/5  =  days for 5 to complete 

x/(5+1) = x/5 - 8     

x/6 = x/5 - 8 

5x/30 - 6x/30 = - 8

     solve for x = 240 worker days 

 

Now for 28 days less:

240/ ( 5 + n) =  240/5 -28      where n = number of additional workers

240/(5+n) = 20 

n = 7 additional workers needed above the original 5 

ElectricPavlov Aug 31, 2023

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