Five workers have been hired to complete a job. If one additional worker is hired, they could complete the job $8$ days earlier. If the job needs to completed $28$ days earlier, how many additional workers should be hired?

Guest Aug 31, 2023

#1**+1 **

x = worker days needed to complete the job

x/5 = days for 5 to complete

x/(5+1) = x/5 - 8

x/6 = x/5 - 8

5x/30 - 6x/30 = - 8

solve for x = 240 worker days

Now for 28 days less:

240/ ( 5 + n) = 240/5 -28 where n = number of additional workers

240/(5+n) = 20

**n = 7 additional workers needed above the original 5 **

ElectricPavlov Aug 31, 2023

#1**+1 **

Best Answer

x = worker days needed to complete the job

x/5 = days for 5 to complete

x/(5+1) = x/5 - 8

x/6 = x/5 - 8

5x/30 - 6x/30 = - 8

solve for x = 240 worker days

Now for 28 days less:

240/ ( 5 + n) = 240/5 -28 where n = number of additional workers

240/(5+n) = 20

**n = 7 additional workers needed above the original 5 **

ElectricPavlov Aug 31, 2023