A jar contains only pennies, nickels, and dimes. The number of dimes is one more than the number of nickles, and the number of pennies is six more than the number of nickels. How many of each denomination are in the jar, if the total value is $4.80?
30 dimes, 29 nickels, and 35 pennies
Let the numbe of nickles = N
The number of pennies =N + 6
The number of dimes = N + 1
0.01 *[N + 6] + 0.05N + 0.10*[N+1] =4.80, solve for N
N = 29 Nickles
29 + 6 = 35 Pennies
29 + 1 =30 Dimes.
