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Can you solve this algebraically?

 

There are two beakers A and B ,which are filled with acid and water in the ratio 4:3 and 5:3 respectively.In what ratio ,the mixture A and B to be mixed so that the ratio of acid and water to be 3:2 in the resultant mixture?

 Oct 10, 2020
 #1
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Add equal parts of water to each beaker as follows:

 

[4/(3 + w)] + [5/(3 +w)] = 3/2, solve for w

 

w =3 parts of additional water added to each beaker, so that you would have the ratio of:

 

Beaker A =4 : 6     and  Beaker B =5 : 6     [4/6 + 5/6] =9 : 6 =3 : 2 of acid to water.

 Oct 10, 2020
 #2
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+2

Take   7 ml from A (or multiple of 7)   and  8 ml (or multiple of 8) from B

            A                                             B

4acid   +   3 water           +      5 acid + 3 water

= 9 acid + 6 water =   3:2    resultant  mixture

 

So    7:8   would be the mix ratio of A :B

 Oct 10, 2020

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