+0

# Algebra problem

0
32
1

The number (\sqrt{2}+\sqrt{3}+1)^3 can be written in the form a\sqrt{2} + b\sqrt{3} + c\sqrt{6} + d, where a, b, and c are integers. What is a+b+c+d?

Jul 24, 2022

#1
+124524
+1

$$(\sqrt{2}+\sqrt{3}+1)^3$$

$$a\sqrt{2} + b\sqrt{3} + c\sqrt{6} + d$$

[ sqrt 2 + sqrt 3  + 1)^3  =

16 + 14 sqrt(2) + 12 sqrt(3) + 6 sqrt(6)

a= 14

b = 12

c = 6

d = 16

Sum =  48

Jul 24, 2022