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# algebra - quadratics. pls help!! thank you

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Let  and  be real numbers such that a-b=4 and a^3-b^3=52

(a) Find all possible values of ab
(b) Find all possible values of a+b
(c) Find all possible values of  and a and b

Apr 9, 2023

#1
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(a) We can use the difference of cubes factorization to solve for ab:

(a−b)(a2+ab+b2)=52

Since a−b=4, we can substitute this value to get:

4(a2+ab+b2)=52

Solving for a2+ab+b2, we get:

a2+ab+b2=13

We can then use the quadratic formula to solve for ab:

ab=2a−b±b2−4ac​​

Substituting a2+ab+b2=13 and a−b=4 into the quadratic formula, we get:

ab=2⋅4−4±42−4⋅13⋅4​​

ab=8−4±−112​​

ab=8−4±4isqrt(7)

Therefore, the possible values of ab are −2isqrt(7),2isqrt(7)​,−4,4​.

(b) We can use the sum of cubes factorization to solve for a+b:

(a+b)(a2−ab+b2)=a3+b3

Since a3−b3=52, we can substitute this value to get:

(a+b)(a2−ab+b2)=52

Solving for a+b, we get:

a+b=a2−ab+b2a3−b3​=1352​=4​

(c) Since we already found that ab can take on the values −2i7sqrt(7),2isqrt(7)​,−4,4, and a+b=4​, we can find all possible values of a and b by substituting these values into the equation a−b=4.

For ab=−2i7​, we get:

a−(−2i7​)=4

a=4−2i7​

For ab=2i7​, we get:

a−(2i7​)=4

a=4+2i7​

For ab=−4, we get:

a−(−4)=4

a=8

For ab=4, we get:

a−4=4

a=8

Therefore, the possible values of a and b are (4−2isqrt(7),8),(4+2isqrt(7)​,8),(8,8)​.

Apr 9, 2023
#2
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a - b=4,

a^3 - b^3=52, solve for a,  b

Use substitution to get:

a = 2 - sqrt(3) and  b = -2 - sqrt(3)

OR:

a = 2 + sqrt(3) and b = sqrt(3) - 2

Apr 9, 2023