One positive integer is 55 less than twice another. The sum of their squares is 185. Find the integers.
okay,
\(x^2+y^2=185\)
\(x+55=2y\)
\((2y-55)^2+y^2=185\)
\(4y-110+y^2=185\)
\(4y+y^2=295\)
\(y^3=\frac{295}{4}\)
wait wait wait, you said x and y were integers....
um.. Melody or Cphil plz help?
ps. 8 and 11 works for the second statement
pps. 13 and 4 also work for the second statement
I'm not sure if this problem is possible since x and y are whold numbers....