+0

# algebra

0
235
1

There are numbers A and B for which

A/(x - 1) + B/(x + 1) = (2x + 1)/(x^2 - 1)

for every number $x \neq \pm 1$. Find B.

May 16, 2021

#1
+2403
0

A/(x - 1) + B/(x + 1) = (A(x+1) + B(x-1))/(x+1)/(x-1) = (2x + 1)/(x^2 - 1)

A(x+1) + B(x-1) = (2x + 1)

(A+B)x + A - B = 2x + 1

A + B = 2

A - B = 1

Can you solve B from here?

=^._.^=

May 16, 2021