+1222 Let $x$ and $y$ be nonnegative real numbers. If $x + y = 25$, then find the minimum value of $6x + 3y.$
+1908 First, let's put y in terms of x to make our lives easier.
We have
\(y=25-x\)
Now, we subsitute it into the second expression and see what we get,
We have
\(6x+3(25-x)\\ 6x+75-3x\\ 3x+75\)
Now, since x must be nonegative, the smallest value it can be is 0. Thus, we have
\(3(0) + 75\\ 75\)
So 75 is our answer.
Thanks! :)
