Algebra

Rewritten in latex, this is \(9y = 3\cdot 6\cdot 27\cdot \frac4{81\cdot 2}\)

Dividing both sides by \(9\) we get \(y = 3\cdot 6\cdot 3\cdot \frac4{81\cdot 2}\). Now it's just math.

 

\(6=2\cdot3\), so we can rewrite this as \(y = 3\cdot 2\cdot 3\cdot 3\cdot \frac4{81\cdot 2}\)

 

The three \(3\)'s can cancel out with the \(81\) to get \(y = 2\cdot\frac4{3\cdot 2}\).

 

The \(2\) and the \(\frac12\) cancel until we get \(y= \frac43\).